learnohub
Question:

If the point P[{x1 +  t(x2 - x1 )}, {y1 + t (y2 - y1 )} divides the join of A(x1 ,y1 ) and B(x2 ,y2 ) internally then prove that t lies between 0 and 1

Answer:

Given, the point P[{x1 +  t(x2 - x1 )}, {y1 + t (y2 - y1 )}] divides the join of A(x1 ,y1 ) and B(x2 ,y2 ) internally.

Let the ratio is k : 1

Now, {x1 +  t(x2 - x1 ), y1 + t (y2 - y1 )} = {(kx2 + x1 )/(k + 1), (ky2 + y1 )/(k + 1)}

Now, x1 +  t(x2 - x1 ) = (kx2 + x1 )/(k + 1)

=> x1 (1 - t) + tx2 =  kx2 /(k + 1) + x1 /(k + 1)

Now, equate coefficient of x2 , we get

=> t = k/(k + 1)

Since k > 0              {since ratio can not be negative}

=> 0 < k/(k + 1) < 1

=> 0 < t < 1

Hence, the value of t always lies between 0 and 1

Not what you are looking for? Go ahead and submit the question, we will get back to you.

learnohub

Classes

  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • ICSE 6
  • ICSE 7
  • ICSE 8
  • ICSE 9
  • ICSE 10
  • NEET
  • JEE

YouTube Channels

  • LearnoHub Class 11,12
  • LearnoHub Class 9,10
  • LearnoHub Class 6,7,8
  • LearnoHub Kids

Overview

  • FAQs
  • Privacy Policy
  • Terms & Conditions
  • About Us
  • NGO School
  • Contribute
  • Jobs @ LearnoHub
  • Success Stories
© Learnohub 2026.