

If the point P[{x1 + t(x2 - x1 )}, {y1 + t (y2 - y1 )} divides the join of A(x1 ,y1 ) and B(x2 ,y2 ) internally then prove that t lies between 0 and 1
Given, the point P[{x1 + t(x2 - x1 )}, {y1 + t (y2 - y1 )}] divides the join of A(x1 ,y1 ) and B(x2 ,y2 ) internally.
Let the ratio is k : 1
Now, {x1 + t(x2 - x1 ), y1 + t (y2 - y1 )} = {(kx2 + x1 )/(k + 1), (ky2 + y1 )/(k + 1)}
Now, x1 + t(x2 - x1 ) = (kx2 + x1 )/(k + 1)
=> x1 (1 - t) + tx2 = kx2 /(k + 1) + x1 /(k + 1)
Now, equate coefficient of x2 , we get
=> t = k/(k + 1)
Since k > 0 {since ratio can not be negative}
=> 0 < k/(k + 1) < 1
=> 0 < t < 1
Hence, the value of t always lies between 0 and 1
